CV9 Master Catalog

6 Specifications subject to change without notice or incurring obligation 6.9 Multi-Power ® Boosters Regulated Supply Controls Final Output Pressure of Booster 3-Way Control Valve Cycle On/Off Valve System Supply Output End Boosted Pressure Output Gage Check Valve Storage Tank Absorbs Pulses System Supply BP Series Booster with Option “L” Limit Valves Check Valve Driving End 5-21-13 To size an Air to Air booster Boyle's Law must be used because air is compressible. Boyle's Law states: “When the temperature of a confined gas remains constant, the volume varies inversely as its absolute pressure.” This can be stated mathematically as a simple equation: ini- tial absolute pressure x initial volume = final absolute pressure x final volume or P 1 x V 1 = P 2 x V 2 Absolute pressure (psia) = gauge pressure (psig) + atmo- spheric pressure (14.7 psi). Consult your distributor or Fabco-Air Engineering for assis- tance with booster sizing. EXAMPLE 1 : Pump cycle, Air to Air Booster Required output = 100 cu. in. per minute @ 250 psi Available air pressure = 70 psi Input Air Usage, Pump Cycle (See Example 1 above; Model BP 2-1/2 X 4 X 4, 20 stroke/min. @ 70 psi) Solution: Power = Required Pressure psig = 250 Available Pressure psig 70 = 3.6 Minimum Required Power Factor Choose either: 2-1/2" Bore – 4 Stage or 4" Bore – 4 Stage (See Sizing Guide on page 6.2) Solution (2-1/2" Bore): Volume - using Boyle's Law V 1 (Initial Volume) = 4.9 cu. in./in. P 1 (Initial Pressure) = 70 + 14.7 = 84.7 P 2 (Final Pressure) = 250 + 14.7 = 264.7 V 2 (Final Volume) = unknown V 2 = P 1 x V 1 = 84.7 x 4.9 = 1.5 cu. in./in. @250 psig P 2 264.7 On the basis of 20 strokes/minute (typical average) Booster stroke = Required Vol/min. vol/in. stroke x strokes/min Booster stroke = 100 = 3.3 in. 1.5 x 20 Model Choice : BP2-1/2 X 4 X 4 Alternate Solution (4" Bore): Volume - using Boyle's Law V 1 (Initial Volume) = 12.6 cu. in./in. P 1 (Initial Pressure) = 70 + 14.7 = 84.7 P 2 (Final Pressure) = 250 + 14.7 = 264.7 V 2 (Final Volume) = unknown V 2 = P 1 x V 1 = 84.7 x 12.6 = 4.0 cu. in./in. @250 psig P 2 264.7 On the basis of 20 strokes/minute (typical average) Booster stroke = Required Vol/min. vol/in. stroke x strokes/min Booster stroke = 100 = 1.25 in. 4.0 x 20 Model Choice : BP4 X 2 X 4 Solution: Pressure = Required Final Pressure = 250 = 67.6 psi regulated input required Booster Power Factor 3.7 Solution: Volume (CFM) = Input Volume/Inch Stroke x Stroke x CPM 1728 cu. in./cu.ft. Input Volume/Inch Stroke = 19.3 (See Sizing Guide on page 6.2), Stroke = 4", CPM= 20 Volume = 19.3 x 4 x 20 = 1544 = 0.89 CFM @ 67.6 psi 1728 1728 Converting Volume to SCFM: SCFM = CFM x psia = .89 x (67.6 + 14.7) = 5.0 SCFM required Atmosphere 14.7

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