CV9 Master Catalog

6 Specifications subject to change without notice or incurring obligation 6.10 Air-to-Air Sizing ( for Air-to-Oil Sizing See Page 6.11) Regulated Supply Controls Final Output Pressure of Booster 3 way 2 Position Valve, Cycle to Boost Input to 4 way before Operating 4 way to Extend Cylinders System Input Check Valve BP Series Booster Driving End Output End Gage Shows Booster Pressure System Input 4 way 5 Port Valve, 2 Pressure Input, High Pressure Rating Work Cylinders System Input 4 way Control Valve Regulated Supply Controls Final Output Pressure of Booster 3 way Valve, Double Pilot BP Series Booster Driving End Output End Gage Shows Booster Pressure Work Cylinders “RV” Sequence Valve Automatically starts Booster when work load is reached Pilot Operated Check Valve 5-21-13 EXAMPLE 2 : One shot cycle, Air to Air Booster to extend cylinders with boosted (high) pressure. Application shown: 2 cylinders, 1-5/8" bore x 4" stroke must extend to full stroke at 145 psi, then retract at system (80 psi) pressure. EXAMPLE 3 : One shot cycle, Air to Air Booster to extend cylinders with low (system) pressure, then boost to high pressure. Application shown: 2 cylinders, 1-5/8" bore x 4" stroke must extend to full stroke at system (80 psi) pressure, then apply full (145 psi) clamp load. Cylinders are to retract at system (80 psi) pressure. Alternate Solution (4" Bore): Stroke = Required Volume = 45.8 = 3.6 in. Volume/Inch Stroke ‡ 12.6 ‡ ‡ For 4" Bore Volume per Inch of Stroke = 12.6 (See Sizing Guide on page 6.2) Model Choice : BP4 X 4 X 2 Solution: Power = Required Pressure psig = 145 Available Pressure psig 80 = 1.8 Minimum Required Power Factor Choose either: 2-1/2" Bore – 2 Stage or 4" Bore – 2 Stage (See Sizing Guide on page 6.2) Solution: Volume - using Boyle's Law V 1 (Initial Volume) = Unknown P 1 (Initial Pressure) = 80 + 14.7 = 94.7 P 2 (Final Pressure) = 145 + 14.7 = 159.7 V 2 (Final Volume) = Volume required in cylinders, plus estimated volume in fittings and tubing V 2 = 2.07 (area of 1-5/8" bore) x 4" (Stroke) x 2 (quantity) + 1.5 (estimate of fittings in this example) = 18.1 cu. in. V 1 = P 2 x V 2 = 159.7 x 18.1 = 30.5 cu. in. P 1 94.7 Note! Add a recommended factor of 25% to 50% to allow for volumetric efficiency and other losses: 30.5 x 150% = 45.8 cu. in. required in booster. Solution (2-1/2" Bore): Stroke = Required Volume = 45.8 = 9.3 in. Volume/Inch Stroke ‡ 4.9 ‡ ‡ For 2-1/2" Bore Volume per Inch of Stroke = 4.9 (See Sizing Guide on page 6.2) Model Choice : BP2-1/2 X 10 X 2 Alternate Solution (4" Bore): Stroke = Required Volume = 18.6 = 1.5 in. Volume/Inch Stroke ‡ 12.6 ‡ ‡ For 4" Bore Volume per Inch of Stroke = 12.6 (See Sizing Guide on page 6.2) Model Choice : BP4 X 2 X 2 Solution: Power = Required Pressure psig = 145 Available Pressure psig 80 = 1.8 Minimum Required Power Factor Choose either: 2-1/2" Bore – 2 Stage or 4" Bore – 2 Stage (See Sizing Guide on Page 6.2) Solution: Volume - using Boyle's Law V 1 (Initial Volume) = Unknown P 1 (Initial Pressure) = 80 + 14.7 = 94.7 P 2 (Final Pressure) = 145 + 14.7 = 159.7 V 2 (Final Volume) = Volume required in cylinders, plus estimated volume in fittings and tubing V 2 = 2.07 (area of 1-5/8" bore) x 4" (Stroke) x 2 (quantity) + 1.5 (estimate of fittings in this example) = 18.1 cu. in. V 1 = P 2 x V 2 = 159.7 x 18.1 = 30.5 cu. in. P 1 94.7 Note! In this cycle, the volume of the cylinders and tubing may be deducted be- cause it is a part of the final volume; thus, 30.5 - 18.1 = 12.4 cu.in. Add a recommended factor of 25% to 50% to allow for volumetric efficiency and other losses: 12.4 x 150% = 18.6 cu. in. required in booster. Solution (2-1/2" Bore): Stroke = Required Volume = 18.6 = 3.8 in. Volume/Inch Stroke ‡ 4.9 ‡ ‡ For 2-1/2" Bore Volume per Inch of Stroke = 4.9 (See Sizing Guide on page 6.2) Model Choice : BP2-1/2 X 4 X 2

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