FGYS Magnetically Coupled Rodless Slides

Page 6 FGYSR Series Magnetically coupled rodless slides 4-19-13 4) Inclined operation (In operating direction) Lo = Distance from mounting surface to load center of gravity (cm) Bore (mm) $OORZDEOH load mass (W A ) (kg) ø10 ƣ ÷ . 3.5cos Ƨ +2(2.2+Lo)sin Ƨ ø15 ƣ ÷ . 5cos Ƨ +2(2.7+Lo)sin Ƨ ø20 ƣ ÷ . 6cos Ƨ +2(2.9+Lo) sin Ƨ Bore (mm) $OORZDEOH load mass (W A ) (kg) ø25 ƣ ÷ . 6cos Ƨ +2(3.4+Lo) sin Ƨ ø32 ƣ ÷ . 7cos Ƨ +2(4.2+Lo)sin Ƨ ø40 ƣ ÷ . 8cos Ƨ +2(5.1+Lo) sin Ƨ Angle Ə K 0°-45° 1 46°-60° 0.9 61°-75° 0.8 76°-90° 0.7 Table K . $QJOH FRHIðFLHQW Example 4– allowable load calculation for FGYSR25 X 650 Given: Lo = 2 cm; ƣ = 0.68; angle = 60°; K = 0.9 (from Table "K" above) Load = = = 5.9 Kg max $OORZDEOH 0.68 x 120 x 0.9 6(0.500)+2(3.4+2)(0.866) ƣ ÷ . 6cos Ƨ +2(3.4+Lo) sin Ƨ Example 5– allowable load calculation for FGYSR25 X 650 Given: Lo = 2 cm; ƣ = 0.68; angle = 60° Load = = = 5.8 Kg max $OORZDEOH 0.68 x 140 7+2(3.4+2)(0.866) ƣ ÷ 7+2(3.4+Lo) sin Ƨ Example 6– allowable load calculation for FGYSR25 X 650 Given: Lo = 2 cm; ƣ = 0.68 Load = = = 5.1 Kg max $OORZDEOH 0.68 x 60 2.0 + 6.0 ƣ ÷ 6.0 + Lo Example 7– allowable load calculation for FGYSR25 X 650 Given: Lo = 2 cm; ƣ = 0.68 Example 8– allowable load calculation for FGYSR25 X 650 Given: Lo = 2 cm; ƣ = 0.68 Force = = = 7.5 Kg max 0.68 x 60 3.4 + 2 ƣ ÷ 3.4 + Lo Load = = = 7.4 Kg max $OORZDEOH 0.68 x 98 7 + 2 ƣ ÷ 7 + Lo 3OHDVH YLVLW KWWS SRUWDO IDEFR DLU FRP FRQðJXUH SKS IRU FXUUHQW SULFLQJ 6SHFLðFDWLRQV DQG SULFHV VXEMHFW WR FKDQJH ZLWKRXW QRWLFH RU LQFXUULQJ REOLJDWLRQ Horizontal Plane Bore (mm) Allowable loadmass (W A ) (kg) ø10 ƣ ÷ 4 + Lo ø20 ƣ ÷ 6.2 + Lo ø15 ƣ ÷ 5.2 + Lo ø32 ƣ ÷ 8.6 + Lo ø40 ƣ ÷ 10.4 + Lo ø25 ƣ ÷ 7.0 + Lo Bore (mm) Allowable drive force (F A ) (kg) ø10 ƣ ÷ 2.2 + Lo ø20 ƣ ÷ 2.9 + Lo ø15 ƣ ÷ 2.7 + Lo ø32 ƣ ÷ 4.2 + Lo ø40 ƣ ÷ 5.1 + Lo ø25 ƣ ÷ 3.4 + Lo Bore (mm) Allowable loadmass (W A ) (kg) ø10 ƣ ÷ 3.5 + Lo ø20 ƣ ÷ 6.0 + Lo ø15 ƣ ÷ 5.0 +Lo ø32 ƣ ÷ 7.0 + Lo ø40 ƣ ÷ 8.0 + Lo ø25 ƣ ÷ 6.0 + Lo 5) Inclined operation (At right angle to operating direction) Bore (mm) $OORZDEOH load mass (W A ) (kg) ø10 ƣ ÷ 4+2(2.2+Lo)sin Ƨ ø15 ƣ ÷ 5.2+2(2.7+Lo)sin Ƨ ø20 ƣ ÷ 6.2+2(2.9+Lo) sin Ƨ Bore (mm) $OORZDEOH load mass (W A ) (kg) ø25 ƣ ÷ 7+2(3.4+Lo)sin Ƨ ø32 ƣ ÷ 8.6+2(4.2+Lo)sin Ƨ ø40 ƣ ÷ 10.4+2(5.1+Lo) sin Ƨ Lo = Distance from center of slide block to load center of gravity (cm) Lo = Distance from mounting surface to load center of gravity (cm) 6) Load center offset in operating direction (Lo) +RUL]RQWDO RSHUDWLRQ 3XVKLQJ ORDG 3XVKHU 8) Horizontal operation (Load lateral offset Lo) F: Drive (from slide block to position Lo) resistance force W [ Ƅ NJ Lo: Distance (cm) from mounting surface to load center of gravity Ƅ )ULFWLRQ FRHIðFLHQW Allowable load mass calculation based on cylinder mounting orientation Lo = Distance from center of slide block to load center of gravity (cm) $OORZDEOH

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